36/64=b^2=

Solution for 36/64=b^2= equation:

36/64=b^2=

We move all terms to the left:

36/64-(b^2)=0

We add all the numbers together, and all the variables

-1b^2+36/64=0

We multiply all the terms by the denominator


-1b^2*64+36=0

Wy multiply elements

-64b^2+36=0

a = -64; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-64)·36
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*-64}=\frac{-96}{-128}
=3/4
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*-64}=\frac{96}{-128}
=-3/4
$